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6x^2-9x=150
We move all terms to the left:
6x^2-9x-(150)=0
a = 6; b = -9; c = -150;
Δ = b2-4ac
Δ = -92-4·6·(-150)
Δ = 3681
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{3681}=\sqrt{9*409}=\sqrt{9}*\sqrt{409}=3\sqrt{409}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-9)-3\sqrt{409}}{2*6}=\frac{9-3\sqrt{409}}{12} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-9)+3\sqrt{409}}{2*6}=\frac{9+3\sqrt{409}}{12} $
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